(3/2)x+(7/2)=2^x

Solution for (3/2)x+(7/2)=2^x equation:

(3/2)x+(7/2)=2^x

We move all terms to the left:

(3/2)x+(7/2)-(2^x)=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+3/2)x-2^x+(+7/2)=0

We multiply parentheses

3x^2-2^x+(+7/2)=0

We get rid of parentheses

3x^2-2^x+7/2=0

We multiply all the terms by the denominator


3x^2*2-2^x*2+7=0

Wy multiply elements

6x^2-4x+7=0

a = 6; b = -4; c = +7;
Δ = b2-4ac
Δ = -42-4·6·7
Δ = -152
Delta is less than zero, so there is no solution for the equation